The value of efficiency eta for a heat engine | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The efficiency $\eta$ of a heat engine is defined as the ratio of the work done $W$ by the engine to the heat $Q_H$ absorbed from the source.$\eta

Vedclass · Accepted Answer

$0$ to $1$

Vedclass · Answer

(A) The efficiency $\eta$ of a heat engine is defined as the ratio of the work done $W$ by the engine to the heat $Q_H$ absorbed from the source.$\eta = \frac{W}{Q_H} = 1 - \frac{Q_L}{Q_H}$According to the second law of thermodynamics,no heat engine can have an efficiency of $1$ $(100\%)$,as it would require the heat rejected to the sink $Q_L$ to be $0$,which is impossible.Also,the efficiency cannot be negative as it would imply the engine is performing work by absorbing heat from a cold reservoir without external work,violating the second law.Therefore,the efficiency $\eta$ always lies between $0$ and $1$ $(0 < \eta < 1)$.

The value of efficiency $\eta$ for a heat engine may lie between

Similar Questions

What is the efficiency of a Carnot engine working between the boiling point and the freezing point of water (in $\%$)?

What is a Carnot cycle? Explain it by drawing a figure.

The efficiency of a Carnot engine is $\eta$ when its hot and cold reservoirs are maintained at temperatures $T_1$ and $T_2$,respectively. To increase the efficiency to $1.5 \eta$,the increase in temperature $(\Delta T)$ of the hot reservoir,while keeping the cold reservoir constant at $T_2$,is

If the temperature of the sink is at absolute zero,then the efficiency of the Carnot engine will be ........ $\%$

$300 \, cal$ of heat is given to a heat engine and it rejects $225 \, cal$ of heat. If the source temperature is $227^{\circ} C$,then the temperature of the sink will be . . . . . . $^{\circ} C$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module