The symbol given below represents:

In a common-emitter transistor,the current gain $\beta$ is $49$. If there is a change of $5.0 \ \mu A$ in the base current,what will be the change in the collector current and the emitter current?

While a collector to emitter voltage is constant in a transistor,the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is

Given below are two statements:
Statement $I:$ In a typical transistor,all three regions emitter,base and collector have same doping level.
Statement $II:$ In a transistor,collector is the thickest and base is the thinnest segment.
In the light of the above statements,choose the most appropriate answer from the options given below.

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios,then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \times \beta_{dc}}$ is:

For a common emitter transistor amplifier, the current gain is $\beta = 100$. Given the input voltage $V_{in} = 1 \text{ mV}$, input resistance $R_{in} = 1 \text{ k}\Omega$, and load resistance $R_L = 10 \text{ k}\Omega$, calculate the output voltage $V_{out}$ in $\text{V}$.