For a transistor,alpha_{dc} and beta_{dc} are | vedclass

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(B) We know the relationship between the current gain parameters $\alpha_{dc}$ and $\beta_{dc}$ of a transistor is given by $\beta_{dc} = \frac{\alpha

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(B) We know the relationship between the current gain parameters $\alpha_{dc}$ and $\beta_{dc}$ of a transistor is given by $\beta_{dc} = \frac{\alpha_{dc}}{1 - \alpha_{dc}}$.Rearranging this,we get $\frac{1}{\beta_{dc}} = \frac{1 - \alpha_{dc}}{\alpha_{dc}} = \frac{1}{\alpha_{dc}} - 1$.This implies $\frac{1}{\alpha_{dc}} - \frac{1}{\beta_{dc}} = 1$.Taking the common denominator,we get $\frac{\beta_{dc} - \alpha_{dc}}{\alpha_{dc} 	imes \beta_{dc}} = 1$.

For a transistor,$\alpha_{dc}$ and $\beta_{dc}$ are the current ratios,then the value of $\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc} \times \beta_{dc}}$ is:

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