The statement (p rightarrow q) rightarrow ((s | vedclass

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(D) We evaluate the logical expression using the laws of logic: $(p$ $\rightarrow q)$ $\rightarrow ((\sim p$ $\rightarrow q)$ $\rightarrow q)$ $\equiv

Vedclass · Accepted Answer

a tautology.

Vedclass · Answer

(D) We evaluate the logical expression using the laws of logic: $(p$ $\rightarrow q)$ $\rightarrow ((\sim p$ $\rightarrow q)$ $\rightarrow q)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow ((p \vee q)$ $\rightarrow q)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow (\sim(p \vee q) \vee q)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow ((\sim p \wedge \sim q) \vee q)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow ((\sim p \vee q) \wedge (\sim q \vee q))$ $\equiv (p$ $\rightarrow q)$ $\rightarrow ((\sim p \vee q) \wedge T)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow (\sim p \vee q)$ $\equiv (p$ $\rightarrow q)$ $\rightarrow (p$ $\rightarrow q)$ $\equiv T$ Since the result is always true,the statement is a tautology.

The statement $(p$ $\rightarrow q)$ $\rightarrow ((\sim p$ $\rightarrow q)$ $\rightarrow q)$ is

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