The last column in the truth table of the sta | vedclass

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$TTTT$

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(C) Let us construct the truth table for the given statement pattern: $1$. $p$ | $q$ | $\sim p$ | $\sim q$ | $(q \wedge \sim p)$ | $p \rightarrow (q \wedge \sim p)$ | $(p \vee \sim q)$ | $(p \vee \sim q) \wedge p$ | $[p \rightarrow (q \wedge \sim p)] \vee [(p \vee \sim q) \wedge p]$ $2$. $T$ | $T$ | $F$ | $F$ | $F$ | $F$ | $T$ | $T$ | $T$ $3$. $T$ | $F$ | $F$ | $T$ | $F$ | $F$ | $T$ | $T$ | $T$ $4$. $F$ | $T$ | $T$ | $F$ | $T$ | $T$ | $F$ | $F$ | $T$ $5$. $F$ | $F$ | $T$ | $T$ | $F$ | $T$ | $T$ | $F$ | $T$ Thus,the last column values are $T, T, T, T$.

The last column in the truth table of the statement pattern $[p \rightarrow (q \wedge \sim p)] \vee [(p \vee \sim q) \wedge p]$ is

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