(D) Using the equation of motion $v^2 = u^2 + 2as$:For the first distance $S$,the final velocity is $2u$:$(2u)^2 = u^2 + 2aS \Rightarrow 4u^2 = u^2 +

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(D) Using the equation of motion $v^2 = u^2 + 2as$:For the first distance $S$,the final velocity is $2u$:$(2u)^2 = u^2 + 2aS \Rightarrow 4u^2 = u^2 + 2aS \Rightarrow 2aS = 3u^2$.Now,for the total distance $2S$,let the final velocity be $v'$:$(v')^2 = u^2 + 2a(2S) = u^2 + 2(2aS)$.Substituting $2aS = 3u^2$ into the equation:$(v')^2 = u^2 + 2(3u^2) = u^2 + 6u^2 = 7u^2$.Therefore,$v' = \sqrt{7} u$.

Class 11 Physics Motion in Straight Line Uniformly Accelerated Motion

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The speed of a body moving with uniform acceleration is $u$. This speed is doubled while covering a distance $S$. When it covers an additional distance $S$,its speed would become

A
$\sqrt{3} u$
B
$\sqrt{5} u$
C
$\sqrt{11} u$
D
$\sqrt{7} u$

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Motion in Straight Line

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Uniformly Accelerated Motion

The acceleration $a$ in $m/s^2$ of a particle is given by $a = 3t^2 + 2t + 2$,where $t$ is the time. If the particle starts with an initial velocity $u = 2\,m/s$ at $t = 0$,then the velocity at the end of $2\,s$ is:

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$A$ rifle bullet loses $1/20^{th}$ of its velocity in passing through a wooden plank. The least number of planks required to stop the bullet is :-

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$A$ body is moving from rest under constant acceleration. Let $S_1$ be the displacement in the first $(p - 1) \ s$ and $S_2$ be the displacement in the first $p \ s$. The displacement in the $(p^2 - p + 1)^{th} \ s$ will be:

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The velocity $v$ of a particle as a function of its position $x$ is expressed as $v = \sqrt{c_1 - c_2 x}$,where $c_1$ and $c_2$ are positive constants. The acceleration of the particle is

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When are the acceleration and average acceleration equal for a moving object?

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The speed of a body moving with uniform acceleration is $u$. This speed is doubled while covering a distance $S$. When it covers an additional distance $S$,its speed would become

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The acceleration $a$ in $m/s^2$ of a particle is given by $a = 3t^2 + 2t + 2$,where $t$ is the time. If the particle starts with an initial velocity $u = 2\,m/s$ at $t = 0$,then the velocity at the end of $2\,s$ is:

$A$ rifle bullet loses $1/20^{th}$ of its velocity in passing through a wooden plank. The least number of planks required to stop the bullet is :-

$A$ body is moving from rest under constant acceleration. Let $S_1$ be the displacement in the first $(p - 1) \ s$ and $S_2$ be the displacement in the first $p \ s$. The displacement in the $(p^2 - p + 1)^{th} \ s$ will be:

The velocity $v$ of a particle as a function of its position $x$ is expressed as $v = \sqrt{c_1 - c_2 x}$,where $c_1$ and $c_2$ are positive constants. The acceleration of the particle is

When are the acceleration and average acceleration equal for a moving object?

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