The solution set of the inequalities 4x + 3y | vedclass

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(A) To find the feasible region,we analyze the given inequalities:$1$. $4x + 3y \leq 60$: This represents the region on or below the line passing thro

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$S_2$ region

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(A) To find the feasible region,we analyze the given inequalities:$1$. $4x + 3y \leq 60$: This represents the region on or below the line passing through $(15, 0)$ and $(0, 20)$.$2$. $y \geq 2x$: This represents the region on or above the line passing through $(0, 0)$ and $(3, 6)$.$3$. $x \geq 3$: This represents the region to the right of the vertical line $x = 3$.$4$. $x, y \geq 0$: This represents the first quadrant.By testing a point $(4, 10)$ which lies in the $S_2$ region:- $4(4) + 3(10) = 16 + 30 = 46 \leq 60$ (True)- $10 \geq 2(4) = 8$ (True)- $4 \geq 3$ (True)- $4, 10 \geq 0$ (True)Since all conditions are satisfied,the solution set is represented by the $S_2$ region.

The solution set of the inequalities $4x + 3y \leq 60$,$y \geq 2x$,$x \geq 3$,$x, y \geq 0$ is represented by which region?

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