The solution of the equation $(1 + x^2)\frac{dy}{dx} = 1$ is
- A$y = \log(1 + x^2) + c$
- B$y + \log(1 + x^2) + c = 0$
- C$y - \log(1 + x) = c$
- D$y = \tan^{-1}x + c$
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