The solubility of barium iodate in an aqueous solution prepared by mixing $200 \ mL$ of $0.010 \ M$ barium nitrate with $100 \ mL$ of $0.10 M$ sodium iodate is $X \times 10^{-6} mol dm ^{-3}$. The value of $X$ is $.....$
Use: Solubility product constant $\left(K_{ sp }\right)$ of barium iodate $=1.58 \times 10^{-9}$

  • A
    $3.95$
  • B
    $4.95$
  • C
    $5.95$
  • D
    $6.95$

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