During the electrolysis of cryolite,aluminium | vedclass

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Question

(B) During the electrolysis of cryolite $(Na_3AlF_6)$,the reactions are:At Cathode: $Al^{3+} + 3e^- \rightarrow Al$At Anode: $2F^- \rightarrow F_2 + 2

Vedclass · Accepted Answer

$2:3$

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(B) During the electrolysis of cryolite $(Na_3AlF_6)$,the reactions are:At Cathode: $Al^{3+} + 3e^- \rightarrow Al$At Anode: $2F^- \rightarrow F_2 + 2e^-$To balance the electrons,multiply the cathode reaction by $2$ and the anode reaction by $3$:Cathode: $2Al^{3+} + 6e^- \rightarrow 2Al$Anode: $6F^- \rightarrow 3F_2 + 6e^-$The overall reaction is: $2Al^{3+} + 6F^- \rightarrow 2Al + 3F_2$Therefore,the molar ratio of $Al$ to $F_2$ is $2:3$.

During the electrolysis of cryolite,aluminium and fluorine are formed in ........ molar ratio :

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