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(C) The Trapezoidal rule for $n$ intervals of width $h$ is given by:$\int_{x_1}^{x_n} y \, dx \approx \frac{h}{2} [y_1 + 2(y_2 + y_3 + \dots + y_{n-1}

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(C) The Trapezoidal rule for $n$ intervals of width $h$ is given by:$\int_{x_1}^{x_n} y \, dx \approx \frac{h}{2} [y_1 + 2(y_2 + y_3 + \dots + y_{n-1}) + y_n]$Here,the values are $x_1=1, x_2=2, x_3=3, x_4=4$,so the interval width $h = x_{i+1} - x_i = 1$.The corresponding $y$ values are $y_1=0.7111, y_2=0.7222, y_3=0.7333, y_4=0.7444$.Substituting these into the formula:$\int_1^4 y \, dx \approx \frac{1}{2} [0.7111 + 2(0.7222 + 0.7333) + 0.7444]$$\int_1^4 y \, dx \approx \frac{1}{2} [0.7111 + 2(1.4555) + 0.7444]$$\int_1^4 y \, dx \approx \frac{1}{2} [0.7111 + 2.9110 + 0.7444]$$\int_1^4 y \, dx \approx \frac{1}{2} [4.3665]$$\int_1^4 y \, dx \approx 2.18325 \approx 2.1833$

$x$	$1$	$2$	$3$	$4$
$y$	$0.7111$	$0.7222$	$0.7333$	$0.7444$

Using the Trapezoidal rule,find the approximate value of $\int_1^4 y \, dx$ based on the following table:
$x$ $1$ $2$ $3$ $4$
$y$ $0.7111$ $0.7222$ $0.7333$ $0.7444$
(in $.1833$)

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Using the Trapezoidal rule,find the approximate value of $\int_1^4 y \, dx$ based on the following table:$x$$1$$2$$3$$4$$y$$0.7111$$0.7222$$0.7333$$0.7444$ (in $.1833$)