The shapes of SOF_4,XeO_2F_2 and ClF_3 are re | vedclass

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(A) $1$. For $SOF_4$: The central atom $S$ has $6$ valence electrons. It forms $4$ bonds with $F$ and $1$ double bond with $O$. The steric number is $

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Trigonal bipyramidal,see-saw and $T$-shape

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(A) $1$. For $SOF_4$: The central atom $S$ has $6$ valence electrons. It forms $4$ bonds with $F$ and $1$ double bond with $O$. The steric number is $5$ ($4$ sigma bonds + $1$ pi bond is not counted in $VSEPR$,but the double bond occupies one equatorial position). The geometry is trigonal bipyramidal with no lone pairs,so the shape is trigonal bipyramidal.$2$. For $XeO_2F_2$: The central atom $Xe$ has $8$ valence electrons. It forms $2$ single bonds with $F$ and $2$ double bonds with $O$. The steric number is $4$ (bonds) + $1$ lone pair = $5$. The lone pair occupies an equatorial position,resulting in a see-saw shape.$3$. For $ClF_3$: The central atom $Cl$ has $7$ valence electrons. It forms $3$ bonds with $F$ and has $2$ lone pairs. The steric number is $3 + 2 = 5$. The lone pairs occupy equatorial positions,resulting in a $T$-shape.Thus,the shapes are trigonal bipyramidal,see-saw,and $T$-shape.

The shapes of $SOF_4$,$XeO_2F_2$ and $ClF_3$ are respectively:

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