Which of the following pairs of species have | vedclass

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(C) $1$. $NO_2^+$ is linear ($sp$ hybridization),while $NO_2^-$ is bent ($sp^2$ hybridization). $2$. $PCl_5$ is trigonal bipyramidal ($sp^3d$ hybridiz

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$XeF_4$ and $ICl_4^-$

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(C) $1$. $NO_2^+$ is linear ($sp$ hybridization),while $NO_2^-$ is bent ($sp^2$ hybridization). $2$. $PCl_5$ is trigonal bipyramidal ($sp^3d$ hybridization),while $BrF_5$ is square pyramidal ($sp^3d^2$ hybridization). $3$. $XeF_4$ has $sp^3d^2$ hybridization with two lone pairs,resulting in a square planar shape. $ICl_4^-$ also has $sp^3d^2$ hybridization with two lone pairs,resulting in a square planar shape. Therefore,$XeF_4$ and $ICl_4^-$ have an identical shape.

List-$I$ (Species)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(a)$ $XeF_{2}$	$(i)$ $0$
$(b)$ $XeO_{2}F_{2}$	$(ii)$ $1$
$(c)$ $XeO_{3}F_{2}$	$(iii)$ $2$
$(d)$ $XeF_{4}$	$(iv)$ $3$

Which of the following pairs of species have an identical shape?

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