Which is the CORRECT relation of bond angles? | vedclass

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(B) In $NH_3$,the bond angle is $107^o$ due to $sp^3$ hybridization and lone pair-bond pair repulsion.In $(CH_3)_3N$,the bond angle is approximately $

Vedclass · Accepted Answer

$(SiH_3)_3N > (CH_3)_3N > NH_3$

Vedclass · Answer

(B) In $NH_3$,the bond angle is $107^o$ due to $sp^3$ hybridization and lone pair-bond pair repulsion.In $(CH_3)_3N$,the bond angle is approximately $108^o$ because the bulky methyl groups cause more repulsion than the smaller $H$ atoms.In $(SiH_3)_3N$,the nitrogen atom is $sp^2$ hybridized with a bond angle of $120^o$ because the lone pair of $N$ engages in $p\pi-d\pi$ back bonding with the empty $d$ orbitals of $Si$.Therefore,the correct order of bond angles is $(SiH_3)_3N > (CH_3)_3N > NH_3$.

Column-$I$	Column-$II$ (Shape)
$A$. $SF_4$	$1$. Tetrahedral
$B$. $BrF_3$	$2$. Pyramidal
$C$. $BrO_3^-$	$3$. See-Saw shaped
$D$. $NH_4^+$	$4$. Bent $T$-shaped

Which is the $CORRECT$ relation of bond angles?

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Column-$I$ Column-$II$ (Shape)

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