The shape of XeF^{+}_3 is | vedclass

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(C) The central atom $Xe$ has $8$ valence electrons.For $XeF^{+}_3$,the number of valence electrons is $8 + 3(7) - 1 = 28$.The number of electron pair

Vedclass · Accepted Answer

Bent $T$-shape

Vedclass · Answer

(C) The central atom $Xe$ has $8$ valence electrons.For $XeF^{+}_3$,the number of valence electrons is $8 + 3(7) - 1 = 28$.The number of electron pairs around $Xe$ is calculated as:$Steric \ number = \frac{1}{2} (V + M - C + A) = \frac{1}{2} (8 + 3 - 1) = 5$.With $5$ electron pairs,the hybridization is $sp^3d$.There are $3$ bond pairs and $2$ lone pairs on the $Xe$ atom.According to $VSEPR$ theory,the $2$ lone pairs occupy the equatorial positions to minimize repulsion.This results in a bent $T$-shape for the $XeF^{+}_3$ ion.

$I. SnCl_2$	$II. BeF_2$
$III. SO_2$	$IV. NO_2^+$
$V. C_2H_2$

List-$I$	List-$II$
$(P)$ $XeF_2$	$(5)$ Trigonal bipyramidal and three lone pairs of electrons
$(Q)$ $XeF_4$	$(3)$ Square planar and two lone pairs of electrons
$(R)$ $XeO_3$	$(2)$ Pyramidal and one lone pair of electrons
$(S)$ $XeO_3F_2$	$(4)$ Trigonal bipyramidal and no lone pairs of electrons

The shape of $XeF^{+}_3$ is

Similar Questions

Which of the following substances has the minimum bond angle?

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$I. SnCl_2$ $II. BeF_2$

$III. SO_2$ $IV. NO_2^+$

$V. C_2H_2$

Which of the following is $INCORRECT$?

Which of the following structures of a molecule is expected to have three bond pairs and one lone pair of electrons?

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