Which of the following structures of a molecu | vedclass

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(C) According to $VSEPR$ theory:For tetrahedral geometry: No. of electron pairs $= 4$,Bond pairs $= 4$,Lone pairs $= 0$.For pyramidal geometry (e.g.,$

Vedclass · Accepted Answer

Pyramidal

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(C) According to $VSEPR$ theory:For tetrahedral geometry: No. of electron pairs $= 4$,Bond pairs $= 4$,Lone pairs $= 0$.For pyramidal geometry (e.g.,$NH_3$): No. of electron pairs $= 4$,Bond pairs $= 3$,Lone pairs $= 1$.For trigonal planar geometry: No. of electron pairs $= 3$,Bond pairs $= 3$,Lone pairs $= 0$.For octahedral geometry: No. of electron pairs $= 6$,Bond pairs $= 6$,Lone pairs $= 0$.Therefore,the structure with three bond pairs and one lone pair is pyramidal.

$List-I$ (Compound)	$List-II$ (Shape)
$A$. $BrF_5$	$I$. bent
$B$. $[CrF_6]^{3-}$	$II$. square pyramidal
$C$. $O_3$	$III$. trigonal bipyramidal
$D$. $PCl_5$	$IV$. octahedral

Which of the following structures of a molecule is expected to have three bond pairs and one lone pair of electrons?

Similar Questions

The shape of $IF_7$ molecule is

Match $List-I$ with $List-II$.
$List-I$ (Compound) $List-II$ (Shape)
$A$. $BrF_5$ $I$. bent
$B$. $[CrF_6]^{3-}$ $II$. square pyramidal
$C$. $O_3$ $III$. trigonal bipyramidal
$D$. $PCl_5$ $IV$. octahedral

Choose the correct answer from the options given below.

Which of the following is the correct order of increasing number of lone pair of electrons on the central atom?

The correct order of $H-N-H$ bond angles of ammonia,ammonium ion,and amide ion is:

Which molecular geometry is least likely to result from a trigonal bipyramidal electron geometry?

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