Which of the following is INCORRECT? | vedclass

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(A) To determine the electron geometry,we calculate the steric number $(SN)$ using the formula: $SN = 	ext{Number of bonding pairs} + 	ext{Number of

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$ICl_2^- 	o$ Trigonal bipyramidal electron geometry

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(A) To determine the electron geometry,we calculate the steric number $(SN)$ using the formula: $SN = 	ext{Number of bonding pairs} + 	ext{Number of lone pairs}$.$A$. For $ICl_2^-$,the central atom $I$ has $7$ valence electrons. It forms $2$ bonds with $Cl$ and has $3$ lone pairs. $SN = 2 + 3 = 5$. The electron geometry is Trigonal bipyramidal. This statement is correct.$B$. For $NH_3$,the central atom $N$ has $5$ valence electrons. It forms $3$ bonds with $H$ and has $1$ lone pair. $SN = 3 + 1 = 4$. The electron geometry is Tetrahedral. This statement is correct.$C$. For $SnF_4$,the central atom $Sn$ has $4$ valence electrons. It forms $4$ bonds with $F$ and has $0$ lone pairs. $SN = 4 + 0 = 4$. The electron geometry is Tetrahedral. This statement is correct.$D$. For $PBr_{5(g)}$,the central atom $P$ has $5$ valence electrons. It forms $5$ bonds with $Br$ and has $0$ lone pairs. $SN = 5 + 0 = 5$. The electron geometry is Trigonal bipyramidal. This statement is correct.Wait,re-evaluating the options: All provided options describe the correct electron geometries. However,if the question implies a specific error in geometry naming or structure,$ICl_2^-$ is indeed trigonal bipyramidal (linear molecular geometry). Given the standard options,all are technically correct. If forced to choose an error,there might be a typo in the question source. Assuming the question is valid,all statements are correct.

Which of the following is $INCORRECT$?

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