The set of quantum numbers not applicable for | vedclass

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Question

(A) For any electron in an atom,the quantum numbers must satisfy the following rules:$1$. The principal quantum number $n$ can be any positive integer

Vedclass · Accepted Answer

$n=1, l=1, m=1, s=+1/2$

Vedclass · Answer

(A) For any electron in an atom,the quantum numbers must satisfy the following rules:$1$. The principal quantum number $n$ can be any positive integer $(n = 1, 2, 3, \dots)$.$2$. The azimuthal quantum number $l$ can have values from $0$ to $n-1$.$3$. The magnetic quantum number $m$ can have values from $-l$ to $+l$ (including $0$).$4$. The spin quantum number $s$ can be $+1/2$ or $-1/2$.Evaluating the options:- For $n=1$,the only possible value for $l$ is $0$ (since $l - In option $A$,$n=1$ and $l=1$,which violates the rule $l - In option $B$,$n=1$ and $l=1$,which also violates the rule $l < n$. However,typically in multiple-choice questions,if multiple options are invalid,we identify the most fundamental violation. Both $A$ and $B$ are invalid,but $A$ is a standard example of an impossible state.

The set of quantum numbers not applicable for an electron in an atom is

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