The four quantum numbers for the unpaired ele | vedclass

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Question

(B) The atomic number of chlorine $(Cl)$ is $17$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^5$. The unpaired electron is in the $3p$ orb

Vedclass · Accepted Answer

$n = 3, l = 1, m = 0, s = +1/2$

Vedclass · Answer

(B) The atomic number of chlorine $(Cl)$ is $17$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^5$. The unpaired electron is in the $3p$ orbital. For $3p$ orbital: Principal quantum number $(n)$ = $3$. Azimuthal quantum number $(l)$ = $1$. Magnetic quantum number $(m)$ can be $-1, 0, +1$. Spin quantum number $(s)$ = $+1/2$ or $-1/2$. Among the given options,$n = 3, l = 1, m = 0, s = +1/2$ is a valid set of quantum numbers for one of the $p$-orbitals.

The four quantum numbers for the unpaired electron of chlorine $(Cl)$ are:

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