The set A = { x:x in R,,{x^2} = 16 and 2x = 6 | vedclass

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Question

(a) ${x^2} = 16$ ==> $x = \pm 4$

$2x = 6$ ==> $x = 3$

There is no value of $x$ which satisfies both the above equations. Thus, $A = \phi $

Vedclass · Accepted Answer

$\phi $

Vedclass · Answer

(a) ${x^2} = 16$ ==> $x = \pm 4$

$2x = 6$ ==> $x = 3$

There is no value of $x$ which satisfies both the above equations. Thus, $A = \phi $.

The set $A = \{ x:x \in R,\,{x^2} = 16$ and $2x = 6\} $ equals