The resultant of overrightarrow A + overright | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) ${\vec R_1} = \vec A + \vec B$, ${\vec R_2} = \vec A - \vec B$

$R_1^2 + R_2^2 = {\left( {\sqrt {{A^2} + {B^2}} } \right)^2} + {\left( {\sqrt {{

Vedclass · Accepted Answer

$2({A^2} + {B^2})$

Vedclass · Answer

(c) ${\vec R_1} = \vec A + \vec B$, ${\vec R_2} = \vec A - \vec B$

$R_1^2 + R_2^2 = {\left( {\sqrt {{A^2} + {B^2}} } \right)^2} + {\left( {\sqrt {{A^2} + {B^2}} } \right)^2}$=$2\left( {{A^2} + {B^2}} \right)$

The resultant of $\overrightarrow A + \overrightarrow B $ is ${\overrightarrow R _1}.$ On reversing the vector $\overrightarrow {B,} $ the resultant becomes ${\overrightarrow R _2}.$ What is the value of $R_1^2 + R_2^2$

Similar Questions

The value of the sum of two vectors $\overrightarrow A $ and $\overrightarrow B $ with $\theta $ as the angle between them is

If $A$ and $B$ are two non-zero vectors having equal magnitude, the angle between the vectors $A$ and $A - B$ is

Two vectors $\overrightarrow A $and $\overrightarrow B $lie in a plane, another vector $\overrightarrow C $lies outside this plane, then the resultant of these three vectors i.e.,$\overrightarrow A + \overrightarrow B + \overrightarrow C $

Two forces of $10 \,N$ and $6 \,N$ act upon a body. The direction of the forces are unknown. The resultant force on the body may be .........$N$

Two vectors having equal magnitudes $A$ make an angle $\theta$ with each other. The magnitude and direction of the resultant are respectively