Two vectors having equal magnitudes $A$ make an angle $\theta$ with each other. The magnitude and direction of the resultant are respectively
- A$2\,A \cos \frac{\theta}{2}$, along bisector
- B$A \cos \frac{\theta}{2}$, at $45^{\circ}$ from one vector
- C$2\,A \sin \frac{\theta}{2}$, along bisector
- D$A \cos \frac{\theta}{2}$, along bisector
Similar Questions
Two vectors $\overrightarrow{ A }$ and $\overrightarrow{ B }$ have equal magnitudes. If magnitude of $\overrightarrow{ A }+\overrightarrow{ B }$ is equal to two times the magnitude of $\overrightarrow{ A }-\overrightarrow{ B }$, then the angle between $\overrightarrow{ A }$ and $\overrightarrow{ B }$ will be .......................
Two vectors $\overrightarrow{ A }$ and $\overrightarrow{ B }$ have equal magnitudes. If magnitude of $\overrightarrow{ A }+\overrightarrow{ B }$ is equal to two times the magnitude of $\overrightarrow{ A }-\overrightarrow{ B }$, then the angle between $\overrightarrow{ A }$ and $\overrightarrow{ B }$ will be .......................
- [JEE MAIN 2022]
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In the diagram shown in figure
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