The remainder obtained when $1! + 2! + 3! + \ldots + 11!$ is divided by $12$ is

  • A
    $9$
  • B
    $8$
  • C
    $7$
  • D
    $6$

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Similar Questions

The number of integers $n$ such that $100 \leq n \leq 999$ and $n$ contains at most two distinct digits is:

The number of all four-digit numbers which do not have four distinct digits is

Match the items of List-$I$ to the items of List-$II$:
List-$I$ List-$II$
$(A)$ The number of ways of not selecting $(n-r)$ things from $n$ different things $(I)$ $1+n+{ }^n C_2+\ldots+{ }^n C_r$
$(B)$ $(n-r+1) \cdot{ }^n C_{r-1}$ $(II)$ $(r+1) \cdot{ }^n C_{r+1}$
$(C)$ The number of ways of selecting at least $(n-r)$ things from $n$ different things $(III)$ $r\left({ }^n C_r\right)$
$(D)$ $(n-r)\left({ }^{n-1} C_{r-1}+{ }^{n-1} C_r\right)$ $(IV)$ $2^n-1-n-{ }^n C_2-\ldots-{ }^n C_r$
$(V)$ ${ }^n C_{n-r}$

The correct match is:

The number of seven-digit numbers that can be formed by using the digits $1, 2, 3, 5,$ and $7$ such that each digit is used at least once is:

For a set of $5$ true or false questions,no student has written all the correct answers and no two students have given the same sequence of answers. The maximum number of students in the class for this to be possible is

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