The ratio of wavelengths of a proton and a deuteron accelerated by potentials $V_{p}$ and $V_{d}$ is $1 : \sqrt{2}$. Then,the ratio of $V_{p}$ to $V_{d}$ will be:

  • A
    $1 : 1$
  • B
    $\sqrt{2} : 1$
  • C
    $2 : 1$
  • D
    $4 : 1$

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