The ratio in which $B\left(\frac{33}{5}, \frac{28}{5}, \frac{38}{5}\right)$ divides the line segment joining $A(3, 2, 4)$ and $C(9, 8, 10)$ is

  • A
    $2: 1$
  • B
    $1: 3$
  • C
    $3: 2$
  • D
    $5: 3$

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If $A(2,-1,1)$,$B(2,5,1)$,and $C(0,-2,3)$ are the vertices of a triangle,and $D$ is the point of intersection of the side $BC$ and the internal angular bisector of angle $A$,then $AD=$

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