If $P(-3, -2, 4)$,$Q(-9, -8, 10)$,and $R(-5, -4, 6)$ are collinear,then the ratio in which $R$ divides $PQ$ is

Points $A(3, 2, 4)$,$B\left(\frac{33}{5}, \frac{28}{5}, \frac{38}{5}\right)$ and $C(9, 8, 10)$ are given. The ratio in which $B$ divides $\overline{AC}$ is

Find the coordinates of the points which trisect the line segment joining the points $A(2, 1, -3)$ and $B(5, -8, 3)$.

Using the section formula,prove that the three points $A(-4, 6, 10)$,$B(2, 4, 6)$,and $C(14, 0, -2)$ are collinear.

If $m:n$ is the ratio in which the point $\left(\frac{8}{5}, -\frac{1}{5}, \frac{8}{5}\right)$ divides the line segment joining the points $(2, p, 2)$ and $(p, -2, p)$,where $p$ is an integer,then $\frac{3m+n}{3n} =$

If $A(4,3,5)$,$B(0,-2,2)$,and $C(3,2,1)$ are three points,then the coordinates of the point $D$ where the bisector of $\angle BAC$ meets the side $BC$ are: