The ranges and heights for two projectiles pr | vedclass

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(B) The horizontal range of a projectile is given by $R = \frac{u^2 \sin(2	heta)}{g}$.Since $\sin(2 	imes 42^{\circ}) = \sin(84^{\circ})$ and $\sin(

Vedclass · Accepted Answer

$R_{1} = R_{2}$ and $H_{1} < H_{2}$

Vedclass · Answer

(B) The horizontal range of a projectile is given by $R = \frac{u^2 \sin(2	heta)}{g}$.Since $\sin(2 	imes 42^{\circ}) = \sin(84^{\circ})$ and $\sin(2 	imes 48^{\circ}) = \sin(96^{\circ})$,and we know that $\sin(84^{\circ}) = \sin(180^{\circ} - 96^{\circ}) = \sin(96^{\circ})$,the ranges are equal: $R_{1} = R_{2}$.The maximum height of a projectile is given by $H = \frac{u^2 \sin^2 	heta}{2g}$.Since $H$ is proportional to $\sin^2 	heta$,and $\sin(48^{\circ}) > \sin(42^{\circ})$,it follows that $H_{2} > H_{1}$,or $H_{1} Therefore,the correct option is $R_{1} = R_{2}$ and $H_{1} < H_{2}$.

The ranges and heights for two projectiles projected with the same initial velocity at angles $42^{\circ}$ and $48^{\circ}$ with the horizontal are $R_{1}, R_{2}$ and $H_{1}, H_{2}$ respectively. Choose the correct option:

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