The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters $36\, cm$ and $20\, cm$ is (in $cm$)
The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters $36\, cm$ and $20\, cm$ is (in $cm$)
- A
$56$
- B
$42$
- C
$28$
- D
$16$
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