The proposition sim (p vee sim q) vee sim (p | vedclass

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(C) Given the expression $\sim (p \vee \sim q) \vee \sim (p \vee q)$.Using De Morgan's Law,$\sim (A \vee B) \equiv \sim A \wedge \sim B$.So,$\sim (p \

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$\sim p$

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(C) Given the expression $\sim (p \vee \sim q) \vee \sim (p \vee q)$.Using De Morgan's Law,$\sim (A \vee B) \equiv \sim A \wedge \sim B$.So,$\sim (p \vee \sim q) \equiv \sim p \wedge q$ and $\sim (p \vee q) \equiv \sim p \wedge \sim q$.The expression becomes $(\sim p \wedge q) \vee (\sim p \wedge \sim q)$.Using the Distributive Law,we factor out $\sim p$:$\sim p \wedge (q \vee \sim q)$.Since $(q \vee \sim q)$ is a tautology $(T)$,$\sim p \wedge T \equiv \sim p$.

The proposition $\sim (p \vee \sim q) \vee \sim (p \vee q)$ is logically equivalent to

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