The product of the lengths of perpendiculars | vedclass

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(B) The given equation of the hyperbola is $x^2 - 2y^2 = 2$,which can be rewritten as $\frac{x^2}{2} - \frac{y^2}{1} = 1$. Comparing this with the sta

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$2/3$

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(B) The given equation of the hyperbola is $x^2 - 2y^2 = 2$,which can be rewritten as $\frac{x^2}{2} - \frac{y^2}{1} = 1$. Comparing this with the standard form $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$,we get $a^2 = 2$ and $b^2 = 1$. The product of the lengths of the perpendiculars drawn from any point on the hyperbola to its asymptotes is given by the formula $\frac{a^2 b^2}{a^2 + b^2}$. Substituting the values,we get $\frac{2 	imes 1}{2 + 1} = \frac{2}{3}$.

The product of the lengths of perpendiculars drawn from any point on the hyperbola $x^2 - 2y^2 - 2 = 0$ to its asymptotes is

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