The product sqrt[3]{2} cdot sqrt[4]{2} cdot s | vedclass

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Question

We have,

$\sqrt[3]{2} \cdot \sqrt[4]{2} \cdot \sqrt[12]{32}=2^{\frac{1}{2}} 	imes 2^{\frac{1}{4}} 	imes\left(2^{5}ight)^{\frac{1}{12}}=2^{\frac

Vedclass · Accepted Answer

$2$

Vedclass · Answer

We have,

$\sqrt[3]{2} \cdot \sqrt[4]{2} \cdot \sqrt[12]{32}=2^{\frac{1}{2}} 	imes 2^{\frac{1}{4}} 	imes\left(2^{5}ight)^{\frac{1}{12}}=2^{\frac{1}{3}} 	imes 2^{\frac{1}{4}} 	imes 2^{\frac{5}{12}}$

$=2^{\frac{1}{3}+\frac{1}{4}+\frac{5}{12}}=2^{\frac{4+3+5}{12}}=2^{\frac{12}{12}}=2^{1}=2$

Hence, $(c)$ is the correct answer.

The product $\sqrt[3]{2} \cdot \sqrt[4]{2} \cdot \sqrt[12]{32}$ equals

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