The probability that an ordinary or a non-lea | vedclass

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(B) An ordinary year (non-leap year) consists of $365$ days.Dividing $365$ by $7$,we get $365 = 52 	imes 7 + 1$.This means an ordinary year has $52$

Vedclass · Accepted Answer

$1/7$

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(B) An ordinary year (non-leap year) consists of $365$ days.Dividing $365$ by $7$,we get $365 = 52 	imes 7 + 1$.This means an ordinary year has $52$ full weeks and $1$ extra day.The extra day can be any of the $7$ days of the week: {Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}.For the year to have $53$ Sundays,the extra day must be a Sunday.Since there is only $1$ favorable outcome (Sunday) out of $7$ possible outcomes,the probability is $1/7$.

The probability that an ordinary or a non-leap year has $53$ Sundays is

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