From a pack of 52 cards,4 cards are drawn. Wh | vedclass

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(D) Total number of ways to draw $4$ cards from $52$ cards is $n(S) = {}^{52}C_4 = \frac{52 	imes 51 	imes 50 	imes 49}{4 	imes 3 	imes 2 	imes

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(D) Total number of ways to draw $4$ cards from $52$ cards is $n(S) = {}^{52}C_4 = \frac{52 	imes 51 	imes 50 	imes 49}{4 	imes 3 	imes 2 	imes 1} = 270725$.There are $4$ queens in a pack of $52$ cards. If we draw $4$ cards such that there is no queen,we must choose $4$ cards from the remaining $52 - 4 = 48$ cards.Number of favorable outcomes is $n(E) = {}^{48}C_4 = \frac{48 	imes 47 	imes 46 	imes 45}{4 	imes 3 	imes 2 	imes 1} = 194580$.The probability $P(E) = \frac{n(E)}{n(S)} = \frac{194580}{270725}$.Dividing both numerator and denominator by $5$,we get $P(E) = \frac{38916}{54145}$.

From a pack of $52$ cards,$4$ cards are drawn. What is the probability that it has no queen?

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