For any two independent events E_1 and E_2, P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) By De Morgan's Law,we know that $\bar{E}_1 \cap \bar{E}_2 = \overline{E_1 \cup E_2}$.Substituting this into the expression,we get $(E_1 \cup E_2)

Vedclass · Accepted Answer

$< \frac{1}{4}$

Vedclass · Answer

(A) By De Morgan's Law,we know that $\bar{E}_1 \cap \bar{E}_2 = \overline{E_1 \cup E_2}$.Substituting this into the expression,we get $(E_1 \cup E_2) \cap (\overline{E_1 \cup E_2})$.Since the intersection of any set $A$ and its complement $\bar{A}$ is the empty set $\phi$,we have $(E_1 \cup E_2) \cap (\overline{E_1 \cup E_2}) = \phi$.The probability of an empty set is $P(\phi) = 0$.Since $0 < \frac{1}{4}$,the correct option is $A$.

For any two independent events $E_1$ and $E_2,$ $P\{(E_1 \cup E_2) \cap (\bar{E}_1 \cap \bar{E}_2)\}$ is

Similar Questions

$A$ positive integer is selected at random and is divided by $9$. What is the probability that the remainder is equal to $1$ (in $/9$)?

Two dice are thrown. Find the probability that the sum is at least $10$ ?

$A$ box contains $6$ black and $4$ red balls. Three balls are drawn at random. What is the probability that one ball is red and the other two are black?

Three coins are tossed. If at least one of them shows tail,then the probability that all three coins show tail is:

Two cards are drawn from a well-shuffled ordinary deck of $52$ cards. What is the probability that they are both aces if the first card is not replaced?

Vedclass Test Series

Exam Paper Generator

Online Exam Module