The probability that a person chosen at random is left-handed (in handwriting) is $0.1$. Then the probability that in a group of $10$ people there is exactly one left-handed person is:

  • A
    $(0.9)^9$
  • B
    $(0.9)^8$
  • C
    $(0.9)^6$
  • D
    $0.9$

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