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(C) Let $X$ denote the number of kings obtained in $2$ draws. Since the cards are drawn with replacement,this follows a binomial distribution $B(n, p)

Vedclass · Accepted Answer

$\frac{2}{13}$

Vedclass · Answer

(C) Let $X$ denote the number of kings obtained in $2$ draws. Since the cards are drawn with replacement,this follows a binomial distribution $B(n, p)$ where $n = 2$. Probability of getting a king in a single draw is $p = \frac{4}{52} = \frac{1}{13}$. Probability of not getting a king is $q = 1 - p = \frac{12}{13}$. The mean of a binomial distribution is given by $E[X] = np$. Substituting the values,we get: Mean $= 2 	imes \frac{1}{13} = \frac{2}{13}$.

Two cards are drawn successively with replacement from a well-shuffled pack of $52$ cards. The mean of the number of kings is:

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