The probability that a marksman will hit a ta | vedclass

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Question

(A) Let $p$ be the probability of hitting the target, so $p = 1/5$.Let $q$ be the probability of missing the target, so $q = 1 - p = 1 - 1/5 = 4/5$.Fo

Vedclass · Accepted Answer

$1 - (4/5)^{10}$

Vedclass · Answer

(A) Let $p$ be the probability of hitting the target, so $p = 1/5$.Let $q$ be the probability of missing the target, so $q = 1 - p = 1 - 1/5 = 4/5$.For $n = 10$ independent shots, the probability of missing the target in all $10$ shots is $q^{10} = (4/5)^{10}$.The probability of at least one hit is given by $P(	ext{at least one hit}) = 1 - P(	ext{no hits})$.Therefore, $P(	ext{at least one hit}) = 1 - (4/5)^{10}$.

The probability that a marksman will hit a target is given as $1/5$. Then his probability of at least one hit in $10$ shots is:

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