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(D) The set of the first ten natural numbers is $S = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$.The total number of outcomes is $n(S) = 10$.We need to find nu

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$\frac{1}{5}$

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(D) The set of the first ten natural numbers is $S = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$.The total number of outcomes is $n(S) = 10$.We need to find numbers that are both odd and perfect squares within this set.The perfect squares in the set are $1, 4, 9$.Among these,the odd numbers are $1$ and $9$.Thus,the number of favorable outcomes is $n(E) = 2$.The probability $P(E) = \frac{n(E)}{n(S)} = \frac{2}{10} = \frac{1}{5}$.

$A$ number is chosen at random from the first ten natural numbers. The probability that the number is odd and a perfect square is

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