Find the chance of throwing 6 at least once i | vedclass

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(B) The probability of getting a $6$ in a single throw is $p = \frac{1}{6}$.The probability of not getting a $6$ in a single throw is $q = 1 - p = 1 -

Vedclass · Accepted Answer

$[1-(\frac{5}{6})^{6}]$

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(B) The probability of getting a $6$ in a single throw is $p = \frac{1}{6}$.The probability of not getting a $6$ in a single throw is $q = 1 - p = 1 - \frac{1}{6} = \frac{5}{6}$.For $n = 6$ independent throws, the probability of not getting a $6$ in any of the throws is $q^n = (\frac{5}{6})^{6}$.The probability of getting a $6$ at least once is given by $1 - P(	ext{no } 6) = 1 - (\frac{5}{6})^{6}$.

Find the chance of throwing $6$ at least once in six throws with a single die.

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