The probability that a leap year selected ran | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) leap year contains $366$ days,which is equal to $52$ weeks and $2$ extra days.There are definitely $52$ Sundays in the $52$ full weeks.For the rem

Vedclass · Accepted Answer

$\frac{2}{7}$

Vedclass · Answer

(B) leap year contains $366$ days,which is equal to $52$ weeks and $2$ extra days.There are definitely $52$ Sundays in the $52$ full weeks.For the remaining $2$ days,the possible combinations are:$(i)$ Sunday and Monday$(ii)$ Monday and Tuesday$(iii)$ Tuesday and Wednesday$(iv)$ Wednesday and Thursday$(v)$ Thursday and Friday$(vi)$ Friday and Saturday$(vii)$ Saturday and SundayThere are $7$ total possible outcomes for the remaining $2$ days.To have $53$ Sundays,one of the remaining $2$ days must be a Sunday.This occurs in $2$ cases: $(i)$ Sunday and Monday,and $(vii)$ Saturday and Sunday.Therefore,the required probability is $\frac{2}{7}$.

The probability that a leap year selected randomly will have $53$ Sundays is

Similar Questions

The probability of getting a total of $5$ or $6$ in a single throw of $2$ dice is

An anti-aircraft gun can take a maximum of $4$ shots at an enemy plane moving away from it. The probabilities of hitting the plane at the first,second,third,and fourth shots are $0.4, 0.3, 0.2,$ and $0.1,$ respectively. What is the probability that the gun hits the plane?

The probability of an event $A$ happening in one trial is $0.4$. The probability that the event $A$ happens at least once in three independent trials is

$A$ card is drawn from a well-shuffled pack of $52$ cards. The probability of getting a queen of clubs or a king of hearts is:

Let $A, B,$ and $C$ be three mutually independent events. Consider the two statements $S_1$ and $S_2$:
$S_1: A$ and $B \cup C$ are independent.
$S_2: A$ and $B \cap C$ are independent.
Then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module