The probability of getting a total of 5 or 6 | vedclass

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(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the probability of getting a sum of $5$ or $6$

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the probability of getting a sum of $5$ or $6$.Favorable outcomes for a sum of $5$ are: $(1, 4), (2, 3), (3, 2), (4, 1)$,which are $4$ outcomes.Favorable outcomes for a sum of $6$ are: $(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)$,which are $5$ outcomes.Total favorable outcomes = $4 + 5 = 9$.The required probability = $\frac{	ext{Total favorable outcomes}}{	ext{Total possible outcomes}} = \frac{9}{36} = \frac{1}{4}$.

The probability of getting a total of $5$ or $6$ in a single throw of $2$ dice is

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