The principal solutions of cot x + sqrt{3} = | vedclass

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Question

(A) Given the equation $\cot x + \sqrt{3} = 0$. Rearranging the terms,we get $\cot x = -\sqrt{3}$. Since $\cot(\frac{\pi}{6}) = \sqrt{3}$,and the cota

Vedclass · Accepted Answer

$\frac{5 \pi}{6}, \frac{11 \pi}{6}$

Vedclass · Answer

(A) Given the equation $\cot x + \sqrt{3} = 0$. Rearranging the terms,we get $\cot x = -\sqrt{3}$. Since $\cot(\frac{\pi}{6}) = \sqrt{3}$,and the cotangent function is negative in the second and fourth quadrants,we have: $x = \pi - \frac{\pi}{6} = \frac{5 \pi}{6}$ $x = 2 \pi - \frac{\pi}{6} = \frac{11 \pi}{6}$ Thus,the principal solutions are $\frac{5 \pi}{6}$ and $\frac{11 \pi}{6}$.

The principal solutions of $\cot x + \sqrt{3} = 0$ are

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