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(C) The pressure $p$ on a circular plate is given by the formula $p = \frac{F}{A}$,where $F$ is the force and $A$ is the area of the plate. Since the

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$11$

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(C) The pressure $p$ on a circular plate is given by the formula $p = \frac{F}{A}$,where $F$ is the force and $A$ is the area of the plate. Since the plate is circular,$A = \pi R^2$,where $R$ is the radius.Therefore,$p = \frac{F}{\pi R^2}$.Using the rules of propagation of errors,the relative error in $p$ is given by:$\frac{\Delta p}{p} = \frac{\Delta F}{F} + 2 \frac{\Delta R}{R}$.To find the percentage error,we multiply by $100$:$\frac{\Delta p}{p} 	imes 100 = \left( \frac{\Delta F}{F} 	imes 100 ight) + 2 \left( \frac{\Delta R}{R} 	imes 100 ight)$.Given that the percentage error in force $\frac{\Delta F}{F} 	imes 100 = 5 \%$ and the percentage error in radius $\frac{\Delta R}{R} 	imes 100 = 3 \%$,we substitute these values:$	ext{Percentage error in } p = 5 \% + 2(3 \%) = 5 \% + 6 \% = 11 \%$.Thus,the percentage error in the measurement of pressure is $11 \%$.

The pressure on a circular plate is measured by measuring the force on the plate and the radius of the plate. If the errors in measurement of the force and the radius are $5 \%$ and $3 \%$ respectively,the percentage of error in the measurement of pressure is (in $\%$)

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