If $Z=\frac{A^{2} B^{3}}{C^{4}}$, then the relative error in $Z$ will be

  • [JEE MAIN 2022]
  • A

    $\frac{\Delta A }{ A }+\frac{\Delta B }{ B }+\frac{\Delta C }{ C }$

  • B

    $\frac{2 \Delta A }{ A }+\frac{3 \Delta B }{ B }-\frac{4 \Delta C }{ C }$

  • C

    $\frac{2 \Delta A }{ A }+\frac{3 \Delta B }{ B }+\frac{4 \Delta C }{ C }$

  • D

    $\frac{\Delta A }{ A }+\frac{\Delta B }{ B }-\frac{\Delta C }{ C }$

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  • [JEE MAIN 2022]