The pressure in the tyre of a car is four times the atmospheric pressure at $300 \ K$. If this tyre suddenly bursts,its new temperature will be $(\gamma = 1.4)$.

  • A
    $300 \ (4)^{1.4/0.4}$
  • B
    $300 \ \left( \frac{1}{4} \right)^{-0.4/1.4}$
  • C
    $300 \ (2)^{-0.4/1.4}$
  • D
    $300 \ (4)^{-0.4/1.4}$

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