The position (x) of a particle moving along x | vedclass

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Question

(b)
$t=0 	ext { to } t=2 \quad \quad t=6 	ext { to } t=8$
$v=20 \,m / s \quad \quad \quad v=-20 \,m / s$
$a_{	ext {avg }}=\frac{\Delta v}{\Delta

Vedclass · Accepted Answer

$-5$

Vedclass · Answer

(b)
$t=0 	ext { to } t=2 \quad \quad t=6 	ext { to } t=8$
$v=20 \,m / s \quad \quad \quad v=-20 \,m / s$
$a_{	ext {avg }}=\frac{\Delta v}{\Delta t}=\frac{-20-20}{8}=\frac{-40}{8}=-5\,ms ^{-2}$
$a_{	ext {avg }}=-5 \,ms ^{-2}$

The position $(x)$ of a particle moving along $x$-axis varies with time $(t)$ as shown in figure. The average acceleration of particle in time interval $t=0$ to $t=8 s$ is ........... $m / s ^2$

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