(D) Given the equation of the circle: $x^2+y^2-3x-4y+2=0$. Since the circle cuts the $x$-axis,the $y$-coordinate at these points must be $0$. Substitu

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(D) Given the equation of the circle: $x^2+y^2-3x-4y+2=0$. Since the circle cuts the $x$-axis,the $y$-coordinate at these points must be $0$. Substituting $y=0$ into the equation: $x^2 + (0)^2 - 3x - 4(0) + 2 = 0$ $x^2 - 3x + 2 = 0$ Factoring the quadratic equation: $(x-1)(x-2) = 0$ This gives $x=1$ and $x=2$. Therefore,the points of intersection are $(1,0)$ and $(2,0)$.

Class 11 Mathematics 10-1.Circle and System of Circles Equations of circle

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The points where the circle $x^2+y^2-3x-4y+2=0$ cuts the $x$-axis are

AP EAMCET 2021 All AP EAMCET

A
$(1,2) \& (2,0)$
B
$(2,0) \& (3,0)$
C
$(0,2) \& (0,1)$
D
$(1,0) \& (2,0)$

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10-1.Circle and System of Circles

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The points where the circle $x^2+y^2-3x-4y+2=0$ cuts the $x$-axis are

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