The perimeter of a circle is equal to that of a square. Compare their areas.

$AB$ and $CD$ are two parallel chords of a circle lying on the opposite side of the centre and the distance between them is $17 \, cm$. The lengths of $AB$ and $CD$ are $10 \, cm$ and $24 \, cm$ respectively. The radius (in $cm$) of the circle is

The area of a circle is $220 \text{ cm}^2$. The area of a square inscribed in this circle will be (in $\text{cm}^2$):

In the given figure,$ABCD$ is a square of side $14 \ cm$. $E$ and $F$ are mid-points of sides $AB$ and $DC$ respectively. $EPF$ is a semicircle whose diameter is $EF$. $LMNO$ is a square. What is the area (in $cm^2$) of the shaded region?

The area of an isosceles trapezium is $176 \, cm^2$ and the height is $2/11$ of the sum of its parallel sides. If the ratio of the length of the parallel sides is $4:7$,then the length of a diagonal (in $cm$) is

If the perimeter of an isosceles right triangle is $(6+3 \sqrt{2}) \text{ m}$,then the area of the triangle is ... $\text{m}^2$.