The area of an isosceles trapezium is $176 \, cm^2$ and the height is $2/11$ of the sum of its parallel sides. If the ratio of the length of the parallel sides is $4:7$,then the length of a diagonal (in $cm$) is

  • A
    $28$
  • B
    $24$
  • C
    $\sqrt{137}$
  • D
    $2\sqrt{137}$

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