The pairs of compounds which cannot exist tog | vedclass

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(C) Compounds that react with each other cannot exist together in an aqueous solution.$I. NaH_2PO_4 + Na_2CO_3 \rightarrow Na_2HPO_4 + NaHCO_3$ (Acid-

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$I, III, IV$

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(C) Compounds that react with each other cannot exist together in an aqueous solution.$I. NaH_2PO_4 + Na_2CO_3 \rightarrow Na_2HPO_4 + NaHCO_3$ (Acid-base reaction occurs)$II. Na_2CO_3$ and $NaHCO_3$ do not react with each other and can coexist.$III. NaH_2PO_4 + 2NaOH \rightarrow Na_3PO_4 + 2H_2O$ (Acid-base reaction occurs)$IV. NaHCO_3 + NaOH \rightarrow Na_2CO_3 + H_2O$ (Acid-base reaction occurs)Thus,the pairs that cannot exist together are $I, III,$ and $IV$.

The pairs of compounds which cannot exist together in aqueous solution are :
$I. NaH_2PO_4$ and $Na_2CO_3$ $II. Na_2CO_3$ and $NaHCO_3$
$III. NaOH$ and $NaH_2PO_4$ $IV. NaHCO_3$ and $NaOH$

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The pairs of compounds which cannot exist together in aqueous solution are :$I. NaH_2PO_4$ and $Na_2CO_3$ $II. Na_2CO_3$ and $NaHCO_3$$III. NaOH$ and $NaH_2PO_4$ $IV. NaHCO_3$ and $NaOH$